Teaching objectives
A primary-school lab (ages 8-12), very visual: everything is done by painting squares, triangles, honeycomb cells, numbers and countries with a click. Each room sets a colouring rule and asks the student to follow it, to count how many ways there are, or to decide whether it can be done at all.
The thread of the lab is the idea of a neighbour: two squares (or two countries) are neighbours if they share a side, not if they only touch at a point. That idea builds ever stricter rules, colours maps with four colours and, at the end, shows that a good colouring can prove that something is impossible, even when the problem says nothing about colours.
What students learn
- Recognise neighbours on a grid, on a triangle split into little triangles and on a honeycomb, and tell «sharing a side» from «touching at a point».
- Follow rules about neighbours (different colour, «three and one», «no orange touches another»), and see that a rule may leave many solutions, two or just one.
- Count in an orderly way (the hidden squares of a 4 × 4 board: 9 of 2 × 2 and 4 of 3 × 3).
- Look for a maximum and justify it: with 12 colours and two equal cells in every 2 × 2 square, the maximum is 11, and there is a reason why you cannot do better.
- Deduce forced colours (coloured numbers: the product of two different colours gets the third) and recognise a clash that proves a puzzle has no solution.
- Colour maps with few colours; understand why sometimes 2 or 3 are enough and sometimes 4 are needed (the flower with 5 petals), and meet the four colour theorem.
- Use the chessboard colouring as a tool: the beetles on the 5 × 5 board (13 against 12) and walks through every square that cannot start or end where asked.
Key mathematical ideas, by block
A · Neighbouring squares. With two colours and «neighbours of different colours» there are only two colourings: the chessboard and its opposite (on the triangle, the ones pointing up in one colour and the ones pointing down in the other). A square on the edge or in the corner has fewer neighbours, and that decides many rules: in «orange with 3 blue neighbours and blue with 1 orange neighbour» no orange can sit in a corner; on the 4 × 4 board there are two solutions, mirror images of each other, and on the triangle of 16, only one. To prove a maximum you need an example and a reason: nine 2 × 2 squares, each equal pair serves at most two, so 5 repeats are needed and 16 − 5 = 11 colours remain.
B · Coloured numbers. The rule makes colours «spread»: once 2 and 3 are known, 6 is forced, then 12, 18… Sometimes you reason backwards (if 9 were not blue, 18 could not be blue). With {2, 3, 4, 6, 12, 24} the forced colours clash: you do not need to try every way to know there is none.
C · Maps. Neighbours = a shared border. A pizza with 4 or 6 slices can be coloured with 2 colours; one with 5 cannot. The island needs 3. The flower with 5 petals needs 4: the centre uses up one colour and the petals, which form an odd ring, cannot alternate just two. The hard map with 20 countries can also be coloured with 4, like any map (the four colour theorem, proved in 1976 with the help of a computer).
D · Colouring to prove. The chessboard is not in the question: we paint it ourselves. Every step to a neighbour changes colour, so 13 beetles do not fit in 12 squares, a walk through all 25 squares of the 5 × 5 board must start on the colour that has 13, and on the 4 × 4 board you cannot visit every square going from one corner to the opposite one. The lab ends with a colour sudoku.
Numbers checked by brute force in scripts/verify_colorear.mjs.
Room-by-room contents
Room 1 · Who is a neighbour?
On a map, neighbours = a shared border; touching at a point does not count. Pizzas with 4, 5 and 6 slices.
Student tasks
- Colour the 4-slice pizza with 2 colours.
- Whether opposite slices are neighbours (no).
- Colour the 6-slice pizza with 2 colours.
- Whether the 5-slice one works with 2 (no: it needs 3).
Room 2 · The island
An island of 8 countries; the one in the middle touches five.
Student tasks
- Colour it with 4 colours.
- Colour it with 3.
- Why not with 2 (three countries that all touch each other).
Room 3 · The flower
A centre and 5 petals: 4 colours are needed. With 6 petals 3 are enough.
Student tasks
- Colour the 5-petal flower with 4 colours.
- Try with 3 and understand why it cannot be done (odd ring).
- Colour the 6-petal flower with 3.
Room 4 · A hard map
A map of 20 countries and 54 borders (nested frames). A help button paints one country compatible with what is already painted.
Student tasks
- Colour it with 4 colours and no equal neighbours.
Room 5 · Neighbours of another colour
What a neighbour is: it shares a side; touching at a corner does not count; on the edge there are fewer neighbours (highlighted example on a 3 × 3). A 4 × 4 board that starts all blue; tapping a square switches it between blue and orange.
Student tasks
- Paint the 4 neighbours of a yellow square orange.
- Colour the 4 × 4 so that each blue has only orange neighbours and each orange only blue ones (the chessboard).
- How many ways there are (2).
Room 6 · Hidden squares
A 2 × 2 frame follows the pointer over a colourful 4 × 4; each click keeps the square in a gallery. The total is not given.
Student tasks
- Find the 9 squares of 2 × 2.
- Find the 4 of 3 × 3.
- How many squares altogether counting every size (30).
Room 7 · As many colours as you can
A 12-colour palette on a 4 × 4 that starts blue. Condition: two cells of the same colour in every 2 × 2. A square that fails lights up in orange (if several, one, and the text says how many).
Student tasks
- Reach the most different colours (11).
- Why 12 is impossible (9 squares, each pair serves at most 2: 5 repeats).
Room 8 · Three and one
Rule: every orange has 3 blue neighbours and every blue exactly 1 orange neighbour, on the 4 × 4. Two solutions, mirror images of each other.
Student tasks
- Count the orange neighbours of a square (2).
- Colour by the rule.
- How to get the other solution (in a mirror; turning gives the same one).
Room 9 · Neighbouring triangles
A big triangle of 16 little triangles: neighbours across a side (at most 3), not at a tip.
Student tasks
- Colour with two colours and no equal neighbours.
- What the orange ones have in common (they all point the same way).
Room 10 · Rules on the triangle
Neighbour rules with a single solution, checked by brute force.
Student tasks
- Triangle of 9: every orange touches 1 orange and every blue 2 oranges (6 oranges in three pairs).
- Triangle of 16: every orange touches 3 blues and every blue 1 orange (4 oranges, none on the edge).
Room 11 · The honeycomb
A honeycomb of 19 hexagonal cells (the centre one has 6 neighbours).
Student tasks
- How many neighbours the centre cell has (6).
- No orange touches another orange and every blue touches exactly 2 oranges (unique: 7 oranges in a star).
Room 12 · Coloured numbers
Three colours (blue, orange, green). Rule: the product of two numbers of different colours gets the third colour; if they have the same colour, nothing is required. Example with 5, 7, 35 and 175. Tokens are painted with a palette, next to the list of products.
Student tasks
- Colour 2, 3, 6, 12, 18, 24 with 2 blue and 3 orange given (unique: 6 green, 12 orange, 18 blue, 24 green).
- Whether 6 could have had another colour (no).
Room 13 · Ten numbers
2, 3, 4, 6, 8, 9, 12, 16, 18, 27 with 2 blue and 3 orange. Unique solution; 9 and 4 are deduced backwards.
Student tasks
- Colour the ten numbers.
- What the rule says about 2 × 2 = 4 (nothing: same colour).
Room 14 · Six numbers
2, 3, 4, 6, 12, 24: no solution. First a free attempt; after several checks, «do you think it can be done?» and the guided explanation.
Student tasks
- Try it.
- Deduce step by step: 6 green, 12 orange, 24 green, 4 green (because 4 × 6 = 24) and the clash at 3 × 4 = 12.
Room 15 · The beetles
A beetle on every square; they all jump at once to a neighbour. On 4 × 4 every square can end up occupied (they go round in circles); on 5 × 5 it cannot.
Student tasks
- Colour the 5 × 5 like a chessboard.
- Count the squares of each colour (13 and 12).
- Which colour a beetle jumps to (the other one).
- What happens to the 13 beetles (two end up together and a square is left empty).
Room 16 · A walk through all of them
A walk through the 25 squares of the 5 × 5, step by step to neighbours, without repeating.
Student tasks
- Do the walk from the corner.
- Try it from the square next to the corner and explain with the chessboard why it cannot be done (13 against 12).
Room 17 · From corner to corner
A walk through the 16 squares of the 4 × 4.
Student tasks
- From a corner to the next corner.
- From a corner to the opposite one: impossible, because both are the same colour and the walk alternates 8 and 8.
Room 18 · Colour sudoku
4 × 4 with 4 colours: every row, column and corner 2 × 2 square with all four. 6 given squares, unique solution.
Student tasks
- Solve it.
- How many times each colour appears (4).
Rooms to project
The most striking ones to show and discuss in class.